Webb8 apr. 2024 · This is the smallest four digit number divisible by 18, 24 and 32. Hence 1152 is the smallest four digit number divisible by 18, 24 and 32. Note: Students generally make mistakes in factorization of a number which is the crucial step in this question. Factorization always starts from 2 and moves on to higher primes. WebbDivisibility by 3 or 9 [ edit] First, take any number (for this example it will be 492) and add together each digit in the number (4 + 9 + 2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).
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Webb10 okt. 2024 · Given: 24, 15 and 36. To find: Here we have to find the greatest number of 6 digits exactly divisible by 24, 15 and 36. Solution: The greatest 6-digit number $=$ 999999. LCM is the least common multiple of any three numbers and to find the greatest 6-digit number we have to check if 999999 is divisible by the LCM of 24, 15 and 36. Webb1 okt. 2024 · As Stuart has very clearly explained above, to be divisible by 16, 24, 36 and 54, the number should be divisible by 2 4 and 3 3 so the number should be a multiple of 432. Out of the given options, lets eliminate 10320 and 10032 right away because they are not even divisible by 9, forget about by 27. ray guy net worth 2022
Find the greatest number of four digits which is exactly divisible by …
Webb22 feb. 2024 · We know that, the greatest 6 digit number is 999999. Let’s assume that 999999 is divisible by 24, 15 and 36 exactly. Then, the LCM (24, 15 and 36) should also divide 999999 exactly. Finding the prime factors of 24, 15, and 36, we get . 24 = 2 × 2 × 2 × 3 . 15 = 3 × 5 . 36 = 2 × 2 × 3 × 3 . ⇒ L.C.M of 24, 15 and 36 = 360 WebbFour digit numbers (4-digit numbers) are numbers that have four digits in them. They range from 1000 to 9999. Therefore, there are a total of 9000 4-digit numbers. … Webb22 apr. 2024 · For this number to be divisible by 24, 15 and 36, Required number must be divisible by the LCM of 24, 15 and 36 i.e., by 360. Now on dividing six digit greatest number by LCM we get 279 as remainder. Therefore the greatest number of 6 digits exactly divisible by 24, 15 and 36 = Six digit greatest number – remainder = 999999 – 279 = … simple tools paleolithic